### A good answer might be:

Six or seven. To be safe, count on no better than six digits of accuracy. This program uses five place accuracy.

# Apply the Formula

The value in `f10` is used to test if the five digits of accuracy have been reached. We will do this in a moment. Here is the part of the program that uses the formula:

    ## x' = (1/2)(x + n/x)

    ## $f0  ---  n
    ## $f1  ---  1.0
    ## $f2  ---  2.0
    ## $f3  ---  x  : current approx.
    ## $f4  ---  x' : next approx.
    ## $f8  ---  temp
    ## $f10 ---  small value

    loop:
            ___.s   $f4,$f0             #  x' = n
            ___.s   $f4,$f4,$f3         #  x' = n/x
            ___.s   $f4,$f3,$f4         #  x' = x + n/x
            ___.s   $f3,$f4,$f2         #  x = (1/2)(x + n/x)

### QUESTION 10:

But part of each menemonic is missing! Fill them in. You may wish to look at floating point operations.