### A good answer might be:

    1B2 =  1 × sixteen2 + B × sixteen1 +  2 × sixteen0

    1B2 =  110 × 162 + 1110 × 161 + 210 × 160

    1B2 =  110 × 25610 + 1110 × 1610 + 210 ×110

    1B2 =  25610 + 17610 + 210

    1B2 =  43410

# Shifting by one Place

You probably know how in base ten to multiply a number by 10: add a zero to the end. So 83 × 10 = 830. This works because:

    83       =     8 × 101 + 3 × 100

    83  × 10 =  (  8 × 101 + 3 × 100 ) × 10

             =     8 × 102 + 3 × 101

             =     830

The same trick works in any base: if a number is represented by (say) XYZ in base B, then XYZ0 represents that number times B.

### QUESTION 9:

What is sixteen times 8B3 ?