### A good answer might be:

        ori      $7, $0, 146        # put +146 into $7
        addiu    $10,$7,-82         # add -82

The program is much shorter.

# The `subu` Instruction

MIPS has two integer subtraction instructions:

    subu   d,s,t        # $d <-- s - t . No overflow trap.
                        # This is equivalent to $d <-- s + (-t)
                        # where (-t) is reflect-add-one of t.

    sub    d,s,t        # $d <-- s - t . Trap overflow!
                        # This is equivalent to $d <-- s + (-t)
                        # where (-t) is reflect-add-one of t.

### QUESTION 11:

When `ori $d,$0,const` is used to load $d, `const` is 16-bit unsigned binary. Say that you want to load $8 with a negative 86. Will the following work?

    addiu    $8,$0,-86  # $8 <-- -86