Is there a need for an arithmetic shift left instruction?

### A good answer might be:

No. A logical shift left moves zeros into the low-order bit, which is correct for both signed and unsigned integers.

# The `sra` Instruction

Here is the MIPS instruction that performs an arithmetic shift right:

    sra    d,s,shft   #  $d <-- s shifted right
                      #  shft bit positions.
                      #  0 =< shft < 31

Sometimes you need to divide by two. This instruction is faster and more convenient than the `div` instruction.

### QUESTION 14:

Does the `sra` instruction give the correct results for unsigned integers?