    addiu    $8,$0,-86

### A good answer might be:

Yes. The immediate operand -86 is sign-extended to 32 bits then added to a 32-bit zero. The sum (-86) is loaded into $8.

# The Absent Subtract Immediate

You would expect that since there are `add, addu, addi, addiu` and since there are `sub, subu` that there would be subtract immediate instructions. But there are not. The add immediate instruction is used. To subtract 201 from register $10 using an immediate operand, do this:

    addiu    $8,$10,-201    #  $8 <-- $10 - 201

Say that we want to compute `5 × x - 74` where the value `x` is in register $8. MIPS has an integer multiply instruction, but let us say that we don't want to use it. How can `5 × x` be done using the instructions you have seen so far?

### QUESTION 12:

How could you compute `4 × $8 + $8` ?