How can you solve for the allowed range of `x`? (Don't actually do this unless you want to).

### A good answer might be:

The result, `poly` must fit into 32 bits, two's complement. So -231 <= 5x^2 -12x + 97 <= 231 - 1. Further algebraic fussing gives the range of `x`.

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- word alignment
- Byte order: little endian and big endian
- MIPS and SPIM byte order
- address calculation
- lw instruction
- Operation of the lw instruction
- load delay slot
- sw instruction
- lui instruction
- symbolic address
- .word directive
- .data directive
- register use table
- accumulator

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