### A good answer might be:

    1   1 11                                       1    1 11
     1010 1110         0000 0000 0000 0000 0000 0000 1010 1110
     1100 0110         0000 0000 0000 0000 0000 0000 1100 0110
     ---------         ---------------------------------------
     1111 0100         0000 0000 0000 0000 0000 0001 1111 0100

# All Arithmetic is 32-bits

MIPS has no instructions for byte arithmetic nor for halfword arithmetic. For a single operation (such as above), the results in the low-order bytes are the same. The carry out of the high-order bit (of the byte or halfword) is part of the 32-bit result. Further operations may increasingly involve high-order bits. The result after several operations will be a correct result, but may not fit into the original size of the operands.

### QUESTION 9:

Now add a third operand to the previous sum:

     1111 0100         0000 0000 0000 0000 0000 0001 1111 0100
     1010 1100         0000 0000 0000 0000 0000 0000 1010 1100
     ---------         ---------------------------------------