### A good answer might be:

Yes.

# Calculate Each Float

Use the for-loop structure to correctly and safely count. Calculate a new value of the floating point variable each time.

    double x;
    int    j;

    for ( j = 0; j < 100; j++ )
    {
      x = j/10.0;

      // do something with x
    }

Almost always, floating point work should be done with double precision, as above. An even more accurate version of the loop is:

    double x;
    int    j;

    for ( j = 0; j < 160; j++ )
    {
      x = j/16.0;

      // do something with x
    }

This is better because (1/16) is accurately represented in binary.

### QUESTION 19:

Is floating point representation (as used in computers) the same as base two radix notation (as discussed in this chapter)?