Answer:

Off by one.
sum is 7

The try block throws the ArrayIndexOutOfBoundsException when the index j goes beyond the end of the array. The catch block catches it, prints out its message, and then execution continues to the statement after the try/catch structure.

Uncaught Exception

Now examine this program:

import java.util.* ;

public class DivisionPracticeTwo
{
  public static void main ( String[] a ) 
  {
     Scanner scan = new Scanner( System.in  );
     int num=0, div=0 ;

     try
     { 
       System.out.print("Enter the numerator: ");
       num = scan.nextInt();
       System.out.print("Enter the divisor  : ");
       div = scan.nextInt();
       System.out.println( num + " / " + div + " is " + (num/div) + " rem " + (num%div) );
     } 
     catch (ArithmeticException ex )
     { 
       System.out.println("You can't divide " + num + " by " + div);
     } 
     
     System.out.println("The program is now ending.")
  }
}

Say that the user enters bad data for the second integer When control reaches the second scan.nextInt() an exception is thrown. But there is no catch block that matches it, so control leaves the program.

C:\JavaSource>java DivisionPracticeTwo
Enter the numerator: 32
Enter the divisor  : two
Exception in thread "main" java.util.InputMismatchException
 . . . . .

Answer:

Uncaught Exception

QUESTION 17: