Second `LET` Statement

The second LET statement changes the contents of the variable.

LET NUMBER = 45.1      ' put 45.1 into NUMBER (erasing the 23.5)

Since the variable NUMBER already exists, no new memory is found for it.
The value 45.1 replaces the previous contents of NUMBER.

If you think of a variable as a box, the box can only hold one thing. So after the second LET statement:

`NUMBER`
45.1

Now the second PRINT statement executes. It looks into NUMBER, finds 45.1, and prints that to the screen. The PRINT statement does not change the contents of NUMBER.

QUESTION 20:

Look again at the complete program:

' Changing the contents of a variable
'
LET NUMBER =  23.5     ' create NUMBER, put 23.5 into it
PRINT "First", NUMBER  ' look in NUMBER to find a value to print
LET NUMBER = 45.1      ' put 45.1 into NUMBER (erasing the 23.5)
PRINT "Second", NUMBER ' look in NUMBER to find a value to print
END

What do you expect will be printed to the screen?

Answer:

Second LET Statement

QUESTION 20:

Second `LET` Statement